Saturday, December 31, 2016

Youtube daily report Jan 1 2017

Hi!

This episode, we're going to be looking at something that

comes up a huge amount in physics,

especially quantum physics and thermodynamics,

namely, the exponential function e to the x.

Now, don't be frightened. You've already seen it.

I just didn't call it by its name.

It'll help out quite a lot with the notation in the next few episodes

It's sometimes written as exp of x,

usually to avoid having a ton of stuff jammed into a tiny superscript.

It's just another way of writing exactly the same thing.

You might have heard of e as an example of an irrational number,

about 2.718,

and that by putting any number to the power of a whole number

is the same as multiplying that first number by itself,

the second number of times,

and while that's sort of true,

it doesn't really matter here, and confuses things quite a bit.

We're going to start from a more relevant definition of e to the x,

which is that:

e to the zero equals one

and for all values of x, the rate of change in e to the x,

with respect to changes in x, is itself.

In other words, it's derivative is also e to the x.

This may seem like a strange definition,

but there is exactly one function that satisfies these two criteria,

even supposing we don't assume anything about what an exponent is,

and it's actually how e to the x originally came to prominence.

By the first criterion,

the value is one when the exponent, x, is zero,

and by the second criterion,

at that point, the slope must also be one.

As x increases, e to the x increases, initially at the same rate as x,

but as its value increases,

by the second criterion, its slope must also be increasing.

If we take a huge number of tiny steps along,

each time, getting the value, and then updating the slope,

to figure out how fast to go up on the next step,

we can trace out the function.

As the size of steps approaches zero,

the values we will get approach the true values.

We can do the same thing in the opposite direction, to get values for when x less than zero,

just moving down and updating the slope, instead of moving up.

This doesn't work with any other number as the base of the exponential, either.

For example,

the derivative of 2 to the x won't be 2 to the x.

It will be off by some constant factor.

For noise-free quantum physics,

the exponential function is most

commonly used in a very particular way

and we've already seen one we just

weren't calling it that X can be

anything

so if we just replace all axes with

another value let's say five x the

equation should still be true and we get

this this says that the rate of change

in each of the five x with respect to

changes in 5x is equal to eat at the 5x

what's d 5x though

well suppose we start with some value of

x let's call it X 0 and then we add some

amount DX to it

how much did 5x change well 5x starts

out as 5 x 0 and after increasing X it's

five times x0 plus DX or five x 0 plus

5dx that means 5 x increases by 5dx when

x increases by DX

in other words d 5 x equals 5dx that's

just a long-winded way of saying that if

you multiply two numbers by five

the difference is five times larger than

it was

replacing the 5x with 5dx gives us this

so then we can multiply both sides by 5

and get this the number five was

arbitrary so this works for multiplying

X by any value a even if it's a complex

number the case that comes up over and

over in quantum physics is where a is an

imaginary number

like I or negative 7 I but what does

that mean what is e to the power of an

imaginary number

let's suppose a is I since multiplying

by i rotate something a quarter turn in

phase this says that as X changes each

of the IAC's always changes in a

direction whose phase is a quarter-turn

different from the value of e to the ikx

we know that at x equals 0 e to the I

acts will be e to the 0 which is one and

as we saw in previous episodes if you

only ever change something in a

direction that's a quarter-turn

different from its current value it

doesn't change the magnitude it only

rotates the phase at a rate equal to the

magnitude of the derivative which in

this case is 1 Radian per meter since

the magnitude of e to the I ax is 11 x

equals 0 and it never changes its always

magnitude 1 and the phase rotates at one

Radian per meter everywhere

this means that each of the I acts for

any value of x has a phase of X radians

and magnitude 1 if we have e to the ikx

the magnitude of the derivative is k +

the derivative is still a quarter turn

from each of the ikx so the magnitude

would still be one everywhere that the

phase would rotate at k radians per

meter everywhere at position acts the

phase would be KX radians

as you can see each of the ikx is

exactly the starting wave from last time

an interesting property of this is that

since we can reverse the phase rotation

by replacing I with- I and the complex

conjugate of a number just has the phase

negated we know that each of the

negative ikx must be the complex

conjugate of e to the ikx since the

magnitudes of both each of the ikx and e

to the negative x KX r1 and their

complex conjugates of each other

multiplying them together gives the

constant value 1 e to the ikx describes

the initial state of the wave we looked

at last time but we also observed that

the phase changed over time as the wave

move forward since the phase-change by-

h-bar over 2 m times K squared every

second multiplying by time t in seconds

gives the total phase change after time

T combining this phase with the phase KX

from the initial wave means that this

wave function at position X and time T

can be written like this that's super

script is a bit awkward to read so we

can write it using X which means exactly

the same thing as e to the power of the

thing in the parentheses but is easier

to read in this case I sometimes write

at one way and sometimes the other way

depending on how bulky the exponent

books you can double check that if you

plug in 0 for the time one of the terms

disappears so it simplifies back to our

initial wave as i mentioned at the

beginning of this episode this notation

looks a bit complicated but just

remember that whenever you have eaten

the I times anything it has magnitude 1

and the phase is whatever the is x in

this case the phase changes at a

constant rate as you move along X and it

changes at a constant rate as time moves

forward so we have exactly the simple

wave moving forward that we saw last

time

it's just written in a different way

that can be used consistently in other

equations if you remember back

we also found an episode 5 that the

second derivative of the initial wave is

negative K squared times the wave itself

or in this notation the second

derivative of e to the ikx is just

negative K squared times e to the ikx

you can find the same thing by taking

the derivative twice and realizing that

you can take any constant factors from

inside the derivative to outside because

just as we saw before the tip of an

arrow that's k times as long

we'll have to move k times as fast to

rotate the same number of radians per

meter and if the arrow is rotated by a

quarter turn the direction it's moving

will also be rotated by a quarter-turn

if we have multiple variables and we're

only taking the derivative with respect

to one you can just treat the others as

constant values instead of variables for

example these are the derivative with

respect X and the derivative with

respect to t for the time-dependent

solution i glossed over some details

here but I wouldn't worry too much about

them right now we've been using

lowercase K for the angular wave number

in radians per meter when people have an

angular velocity in radians per second

namely how fast something is rotating as

time progresses it's often notated using

the lowercase Greek letter Omega this

wave is rotating at negative H bar over

2m times K squared radians per second so

that would be the angular velocity for

this way we'll be using this notation a

lot in the next few videos because it

will make it much easier to reason about

these waves mathematically when it

starts becoming difficult to visually

follow everything that's going on

see you later

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