This is part six of the stoichiometry 101 series. In this video we're gonna
look at finding grams B when given more A. Here's the plan that we've been using.
I've explained it in the first two videos of this series so do check them
out if you haven't seen them. I'll place the link on the top and in the
description box below. Here is our question. We are given the equation for
combustion of propane and we are asked to find the mass of carbon dioxide that
is produced from 2.6 moles of propane, so, what do we have?
It's 2.6 mole of propane and that is C3J8 and what does the question wants?
It's grams of carbon dioxide which is CO2 since we're dealing with two substances
in this questions, which are C3H8 and CO2. We will call them A and B
respectively. A is for what is given. B is for what we need to find. So, our starting
point is what we have and our ending point is what the question wants. So the
next thing we're gonna do is we're gonna tag our start and end point on our
stoichiometry plan like that. Our start point is mole A and our end point is
grams B. A is C3H8. B is CO2, so, looking at the plan it will take two steps to go
from mole A to grams B. Since the question involves two substances and we need the
coefficient ratio for B over A, we need to first make sure that we have a
balanced equation. If you need a refresher on balancing chemical equation,
I will link the video on the top. From the equation that's given, it looks like it's
already balanced, so, we're good to go. We're now ready to set up the solution.
In step one we'll go from mole A to mole B and in step two we'll go from mole B to
grams B. Step one is to multiply the mole, 2.6 mole will be coefficient ratio B over A
from the balanced equation, coefficient B is the number in front of
CO2, which is three. Coefficient A is the number in front of C3H8, which is one,
since there's no number in front, so, there's no number in front of the term,
it means there's only one. So, we take 2.6 mole and
multiply with 3/1 and that will give us 7.8 mol. That is the mole
of CO2 and in our second and final step we need to multiply what we got from
step one with the molar mass of B. B is carbon dioxide so the molar mass is
44.01 grams per mole, so, we take 7.8t and we
multiply with 44.01 and we get 343.3 grams
or 340 grams if we need to report it in two significant figures.
That's the gram of CO2, which is what the
question wants us to find. To recap, we start off by reading the question to
figure out what is the information that we have and what does the question wants
us to find and then we figure out the pathway using the stoichiometry plan and
before we proceed if the question involves two different substances like A
and B, in this question then we need to make sure that our equation is balanced.
Once we got that sorted out, we follow the set up and we solve the problem.
Following these three steps makes solving stoichiometry problems very easy.
For more examples, do watch the videos in the stoichiometry 101 series.
Hope the video was helpful. Do subscribe and thanks for watching!
you
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